Contents
Our lesson today is about indefinite integrals and the most important rules and different methods for finding integrals, with many solved examples of indefinite integrals. We will also briefly touch on integration by substitution.
If you are looking for more problems to practice, you can read the article Indefinite Integral Problems
What is Integration?
Integration is one of the fundamental operations in calculus, and it is the inverse operation of differentiation. Integration involves finding an antiderivative of a given function, such that the derivative of the antiderivative is the given function. In this article, we will discuss in detail the concept of indefinite integrals, the basic rules used to solve them, and illustrative examples.
What is an Indefinite Integral?
The indefinite integral, symbolized by ∫, is the process of finding all functions whose derivative is the given function. In other words, if f(x) is a function, its indefinite integral is F(x) + C
, where F '(x) = f(x)
and C is an arbitrary constant of integration.
Example: If f(x) = 2x
, its indefinite integral is F(x) = x² + C
, since the derivative of x²
is 2x
.
Why do we add the constant of integration?
We add the constant of integration C to the result of the integral because there is an infinite number of functions whose derivative is the same as the given function. For example, the derivative of each of the functions x²
, x² + 1
, x² - 3
, etc., is 2x
. Therefore, adding the constant of integration represents all possible solutions.
Basic Rules of Indefinite Integrals

There are many basic rules used to calculate indefinite integrals. The most important ones are:
- Integral of a Constant Function:
∫ a dx = ax + C
where a is a numerical constant.
A special case: the integral of 1 is x + C - Integral of a Power Function:
∫ xⁿ dx = (xⁿ⁺¹)/(n+1) + C
where n ≠ -1. - Integral of an Exponential Function:
∫ aˣ dx = aˣ/ln(a) + C: a>0,a≠1
Integral of the natural exponential function∫ eˣ dx = eˣ + C
- Integral of a Fractional Function:
∫ 1/x dx =ln |x| + C
- Integral of a Trigonometric Function:
Integral of∫ sin(x) dx = -cos(x) + C
Integral of∫ cos(x) dx = sin(x) + C
Integral of∫ sec2(x) dx = tan(x) + C
Integral of∫ csc2(x) dx = -cot(x) + C
Integral of∫ sec x(tan x) dx = sec(x) + C
Integral of∫ csc x(cot x) dx = -csc(x) + C
- Integral of Hyperbolic and Inverse Trigonometric Functions: Hyperbolic functions are functions defined by a hyperbola instead of a circle.
Properties of Indefinite Integrals
- Integral of a Sum of Functions:
∫ [f(x) + g(x)] dx = ∫ f(x) dx + ∫ g(x) dx
- Constants:
∫ af(x) dx = a∫ f(x) dx
- Linearity Property:
∫ [af(x) + bg(x)] dx = a∫ f(x) dx + b∫ g(x) dx
where a and b are numerical constants.
Properties of Definite Integrals
Indefinite integrals have many properties, and we will mention 5 of them:
- When the integration limits are swapped, the sign must be inverted.
- A constant can be taken outside the integral limits.
- The integral of a sum/difference of two functions = the integral of the first function ± the integral of the second function.
- The possibility of partial integration.
- The fifth property is a theorem.

Examples of Indefinite Integrals
Here is a collection of examples and practical exercises to help you understand indefinite integrals by applying the previous rules in the solution.
Example 1: Find the integral of the function f(x) = 3x² + 2x - 1
.
Solution: Using the power rule: ∫ xⁿ dx = (xⁿ⁺¹)/(n+1) + C
∫ (3x² + 2x - 1) dx
= 3∫ x² dx + 2∫ x dx - ∫ dx
= x³ + x² - x + C
Example 2: Find the integral of the function f(x) = eˣ + sin(x)
.
Solution: To calculate the integral of the function f(x) = eˣ + sin(x), we apply the basic integration rules.
∫ (eˣ + sin(x)) dx
= ∫ eˣ dx + ∫ sin(x) dx
= eˣ - cos(x) + C
Therefore, the integral of the function f(x) = eˣ + sin(x)
is equal to eˣ - cos(x) + C
where C represents the constant of integration.
Exercises on Indefinite Integrals
Below are some simple problems on indefinite integrals. You can refer to the article Indefinite Integral Problems for more examples and exercises.
Find the following integrals:
∫(2x + 3) dx
∫(4cos(x) - 2sin(x)) dx
∫(x2 - 5x + 1) dx
∫(2ex - 3x) dx
∫(1/x + x3) dx
You can now apply the previous rules to these questions and check the complete solution here:
1. Calculate the integral ∫(2x + 3)dx
using the power rule:
∫(2x + 3) dx = x2 + 3x + C
2. Calculate the integral ∫(4cos(x) - 2sin(x))dx
:
∫(4cos(x) - 2sin(x)) dx = 4sin(x) + 2cos(x) + C
3. Calculate the integral ∫(x2 - 5x + 1)dx
:
∫(x2 - 5x + 1) dx = (x3)/3 - (5x2)/2 + x + C
4. Calculate the integral ∫(2ex - 3x)dx
:
∫(2ex - 3x) dx = 2ex - (3x2)/2 + C
5. Calculate the integral ∫(1/x + x3)dx
:
∫(1/x + x3) dx = ln|x| + (x4)/4 + C
Integration by Substitution
Integration by substitution is a technique used to find the integral of complex functions. This is done by replacing a part of the function with a new variable, thereby simplifying the integral.
Example 1: Find the integral of the function f(x) = x * ex²
.
Solution: To calculate the integral of the function f(x) = x * e^(x²)
, we will use the chain rule for integration. The calculation is as follows: We let u = x²
, and therefore du = 2x dx
.
Using these substitutions, we can replace x dx
with (1/2)du
Thus,
∫ x * ex² dx = (1/2) ∫ eu du
= (1/2) eu + C = (1/2) ex² + C.
Example 2 of Integration by Substitution: Calculate the following integral: ∫(2x * sin(x²)) dx
We apply some simple changes to the function. We let u = x²
, and thus du = 2x dx
. We replace 2x dx
with du
, and simplify the function to:
∫sin(u) du = -cos(u) + C
=-cos(x²) + C
In Conclusion
The indefinite integral is a fundamental tool in calculus and is used to solve many problems in physics, engineering, and other fields. By understanding the basic rules of integration and learning techniques such as integration by substitution, a student can solve a wide range of integrals.
Notes:
- There are many other methods for calculating integrals, such as integration by parts and integration by partial fractions.
- Scientific calculators and specialized software can be used to calculate complex integrals.
Do you have any other questions about indefinite integrals? You can mention them in the comments, and we will try to answer them together.